# Resonance and its applications

### Explanation of question 15

The coil of a tuned circuit has a Q factor of 320 at a particular frequency. If this Q is reduced to 160, the bandwidth will be

1. one-quarter its original value
2. half its original value
3. double its original value
4. four times its original value

The answer is :- 3

Bandwidth = f / Q thus if Q is halved, bandwidth will double

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