# Simple alternating current circuits

### Explanation of question 12

A capacitor has a reactance of 16 when connected to a 50Hz supply. Its capacitance will be approximately

1. 200 F
2. 100 F
3. 200 pF
4. 100 pF

The answer is :- 1 Xc= 1 / (2 x PI x F x C). Therefore C = 1 / (2 x PI x F x Xc) = 1 / (2 x PI x 50 x 16) = approximately 200F

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