# Capacitance

### Explanation of question 6

The circuit between A and B in Fig. 6.1 can be replaced by a single resistor in series with a single capacitor. Their values will be, respectively,

1. 12, 4.8 mfd
2. 12, 20 mfd
3. 32, 4.8 mfd
4. 32, 20 mfd

The answer is :- 2 Equivalent resistance of parallel resistor combination (20+30)/(20x30) = 12 Equivalent capacitance of parallel capacitor combination = 8 + 12 = 20mfd.

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