# Resonance and its applications

### Explanation of question 8

A coil has a Q of 150, and is series resonated across a 6V AC supply. The p.d. across the capacitor will be

1. 6V
2. 8.5V
3. 150V
4. 900V

The answer is :- 4 At resonance, XL and XC will cancel out so that the circuit impedance Z will equal the resistance of the circuit, R. Thus, p.d. across R will equal 6V.

The p.d. across L, VL = VR x Q = 6 x 150 = 900V

There will be an equal (but opposite) voltage developed across the capacitor, i.e. 900V

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