# Resistors in series and parallel; power

### Explanation of question 8

If the circuit in Fig. 3.1 (as in the previous two problems), is connected across a 40V supply, the power dissipated in the 15 resistor will be

1. 9.6W
2. 21.6W
3. 56 W
4. 80W

The answer is :- 1

P.D. across 15 resistor = 12 V,

and the current through 15 resistor = 0.8 A,

so power, P = VI = 12 x 0.8 = 9.6 W

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