# Simple alternating current circuits

### Explanation of question 11

A capacitor is connected across a 200Hz fixed voltage supply. If the frequency is raised to 400Hz, the reactance of the capacitor will be

1. doubled
2. unaltered
3. halved
4. one-quarter the original value

The answer is :- 3 Xc = 1 / (2 x PI x F x C). Thus if the frequency is doubled then the reactance will be halved.

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