# Capacitance

### Explanation of question 2

Two capacitors, of value 10pF and 40pF respectively, are connected in series. An equivalent capacitor will have a value of

1. 8pF
2. 30pF
3. 50pF
4. 400pF

The answer is :- 1 1 / C = 1 / 10 + 1 / 40 where C is in picofarads (pF).

Therefore 1 / C = 5 / 40, so C = 40 / 5 = 8 pF.

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