# Resonance and its applications

### Explanation of question 11

11 A parallel resonant circuit has a coil of inductance 800mH and resistance 8 in parallel with a 5F capacitor. The dynamic resistance will be

1. 200k
2. 160k
3. 20k
4. 20

The answer is :- 3

Dynamic resistance =

= 800x10-3 ÷ 40x10-6

= 20,000 = 20k

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