# Receivers

### Explanation of question 9

A superheterodyne receiver having an IF of 9MHz is tuned to a frequency of 14.3MHz. The local oscillator frequency is greater than the signal frequency.

The second channel (image) frequency will be

1. 5.3MHz
2. 19.6MHz
3. 23.3MHz
4. 32.3MHz

The answer is :- 4 A signal frequency of 14.3 MHz + (2 x 9) MHz, i.e. 32.3 MHz, will cause second channel interference, since this frequency less the local oscillator frequency (23.3 MHz) will give 9MHz.

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